试判断下面每组反应能否用同一个离子方程式表示,若能,写出相应

试判断下面每组反应能否用同一个离子方程式表示,若能,写出相应的离子方程式;若不能,简要说明理由。

(1)CaCO3 、Na2CO3分别跟盐酸反应________________________________。

(2)CuO分别跟稀硫酸、稀盐酸反应________________________________。

(3)H2SO4、K2SO4溶液分别跟Ba(OH)2反应________________________________。

答案

(1)不能。CaCO3难溶应写化学式,其离子方程式为:CaCO3+2H+=Ca2++CO2↑+H2O;Na2CO3易溶于水,在溶液中以Na+和CO32-存在,其离子方程式为:

CO32-+2H+=CO2↑+H2O

(2)可以,CuO+2H+=Cu2++H2O

(3)不能,H2SO4跟Ba(OH)2反应除生成BaSO4外,还有难电离水生成;K2SO4跟Ba(OH)2反应只生成难溶的BaSO4

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