将一物体以水平速度v0抛向一个倾角为α的斜面，物体与斜面相撞时

将一物体以水平速度v₀抛向一个倾角为α的斜面，物体与斜面相撞时的速度与斜面交角为β，如图9，求抛出到与斜面相撞所经时间t后，落点位置物体的速度大小.

图9

答案

解析：如下图所示

由tan(β-α)=

得t=·tan(β-α)

由

·tan(β-α)

得.

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