室温下,对于0.10 mol·L-1的氨水,下列判断正确的是(   ) A.其溶

室温下,对于0.10 mol·L-1的氨水,下列判断正确的是  

A.其溶液的pH=13  

B.加入少量NaOH,溶液中c(NH4+)减小,Kw减小

C.与AlCl3溶液反应的离子方程式为 Al3++3OH­=Al(OH­)3

D.滴加0.10 mol·L-1HNO3溶液到pH=7,溶液中离子浓度关系为:c (NO3) = c(NH4+)> c(H+)=c(OH)

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