在介质中有一沿水平方向传播的简谐横波,一质点由平衡位置竖直向

在介质中有一沿水平方向传播的简谐横波,一质点由平衡位置竖直向上运动,经0.1s到达最大位移处,在这段时间内波传播了0.4m,则这列波

A.周期是0.1s            B.振幅是0.4m    C.波长是0.4m    D.波速是4m/s

答案

D


解析:

质点从平衡位置到达最大位移处的时间为,因此周期为,A错;经0.1s波传播距离为0.4m,则波速,D正确;波长为一个周期内传播的距离,即,C错;题给条件不能确定振幅,B错。试题考查波的传播特性和波的概念,难度较易。

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