已知:2H2(g)+ O2(g)= 2H2O(l) △H = -572 kJ/mol CH4(g)+ 2O2(g)= C

已知2H2g+ O2g= 2H2Ol △H = -572 kJ/mol

CH4g+ 2O2g= CO2g+ 2H2Ol △H = -890 kJ/mol

现有H2CH4的混合气体112L(标准状况),使其完全燃烧生成CO2g)和H2Ol),

若实验测得反应放热3695 kJ,则原混合气体中H2CH4的物质的量之比是:(     

A. 11           B. 23           C. 14           D. 13

答案

D

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