已知H2(g)+Cl2(g)=2HCl(g) △H= ―184.6kJ·mol-1, 则反应HCl(g)=1/2H2(g)+1/2Cl2(g)的△H为 ( )
A.+184.6kJ·mol-
1 B.―92.3kJ·mol-1 C.+92.3kJ D. +92.3kJ·mol-1
已知H2(g)+Cl2(g)=2HCl(g) △H= ―184.6kJ·mol-1, 则反应HCl(g)=1/2H2(g)+1/2Cl2(g)的△H为 ( )
A.+184.6kJ·mol-
1 B.―92.3kJ·mol-1 C.+92.3kJ D. +92.3kJ·mol-1
D