A.ac≥b B.ab≥c
C.bc≥a D.ab≤c
解析
∴1=4logca·logcb≤4·()2
=logc2ab,
即logc2ab≥1.又a,b,c均大于1,
∴logcab>0.∴logcab≥1.∴ab≥c.
答案