在平面直角坐标系中,设三角形ABC的顶点坐标分别,点在线段OA上(

在平面直角坐标系中,设三角形ABC的顶点坐标分别,点在线段OA上(异于端点),设均为非零实数,直线分别交于点EF,一同学已正确算出的方程:,请你求OF的方程:                    

答案

【解析】本小题考查直线方程的求法。画草图,由对称性可猜想

事实上,由截距式可得直线,直线,两式相减得,显然直线ABCP的交点F满足此方程,又原点O也满足此方程,故为所求的直线OF的方程。

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