三棱台ABC-A1B1C1中,AB∶A1B1=1∶2,则三棱锥A1—ABC,B—A1B1C,C—A1B1C1

三棱台ABC-A1B1C1中,AB∶A1B1=1∶2,则三棱锥A1—ABC,B—A1B1C,C—A1B1C1的体积之比为(    )

A.1∶1∶1           B.1∶1∶2              C.1∶2∶4               D.1∶4∶4

答案

解析:

如图所示,三棱锥A1—ABC的顶点看作A1,底面看作ABC;三棱锥A1B1C1的顶点看作C,底面看作A1B1C1;三棱锥B—A1B1C可看作棱台减去两个三棱锥A1—ABC和C—A1B1C1后剩余的几何体,分别求几何体的体积,然后相比即可.

设棱台的高为h1,S△ABC=S,则.

S△ABC·h=1Sh,

又V= (S+4S+2S)=

.

∴体积比为1∶2∶4.

答案:

C

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