先化简,再求值:(x+y)(x﹣y)+y(x+2y)﹣(x﹣y)2,其中x=2+,y=2﹣.
解:(x+y)(x﹣y)+y(x+2y)﹣(x﹣y)2
=x2﹣y2+xy+2y2﹣x2+2xy﹣y2
=3xy,
当x=2+,y=2﹣时,原式=3×(2+)(2﹣)=3.
【点评】本题考查整式的混合运算﹣化简求值,解答本题的关键是明确整式的化简求值的计算方法.