如图所示,平行直线表示电场线,但未标方向,带电为+10-2C的微粒

如图所示,平行直线表示电场线,但未标方向,带电为+10-2C的微粒在电场中只受电场力作用,由A点移到B点,动能损失0.1J,若A点电势为-10V,则( )

A.B点的电势为10伏               B.电场线方向从右向左

C.微粒的运动轨迹可能是轨迹1      D.微粒的运动轨迹可能是轨迹2

答案

BC


解析:

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