河上有抛物线型拱桥,当水面距拱桥顶5米时,水面宽为8米,一小船

河上有抛物线型拱桥,当水面距拱桥顶5米时,水面宽为8米,一小船宽4米,高2米,载货后船露出水面上的部分高0.75米,问水面上涨到与抛物线拱顶相距多少米时,小船开始不能通航?

答案

2米


解析:

如图建立直角坐标系,

设桥拱抛物线方程为,由题意可知,

B(4,-5)在抛物线上,所以,得

    当船面两侧和抛物线接触时,船不能通航,设此时船面宽为AA’,则A(),由,又知船面露出水面上部分高为0.75米,所以=2米

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