(8分)体育活动中也包含很多物理知识。下表是体重为600N的杨威

(8分)体育活动中也包含很多物理知识。下表是体重为600N的杨威同学的一次体育测试成绩:

 

请你根据表格中提供的信息进行下列有关计算:(g取10N/kg)

(1)杨威同学站立时,脚与地面的总接触面积为400cm2,则他对地面的压强为多大?

(2)图中,杨威同学在做俯卧撑,A点为此时的重心,O为支点,请你根据图中数据求出支持力F的大小;

(3)杨威同学用4s把杠铃举起了2m,则他举起杠铃的功率是多少?

 

答案

(1)1.5×104Pa   (2) 360N  (3) 150w

解析:解:(1)p= F/S= G /S=600N/400×10-4 m2=1.5×104 Pa

 (2) 根据杠杆平衡条件 F1L1=F2L2可得

F·OC=G·OB

F=( G ·OB)/OC=(600N×0.9m)/(0.9m+0.6m)=360N

(3)F’=G’= m’g=30kg×10N/kg=300N

P=W/t= F’s/t=300N×2m/4s=150w

 

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