已知函数. (I)将写成的形式,并求其图象对称中心的横坐标; (II

已知函数.

(I)将写成的形式,并求其图象对称中心的横坐标;

(II)如果△ABC的三边a、b、c满足b2= a c,且边b所对的角为,试求的范围及此时函数的值域.

答案

(I)对称中心的横坐标为,(k∈Z).  

(II)0<x≤f(x)的值域为(2,1+).     


解析:

(I)f(x) =+(1+)=++

  =sin(+)+.由sin(+)= 0,即+=kπ(k∈Z),

得x=(k∈Z),即对称中心的横坐标为,(k∈Z).  

(II)由已知b2=ac,得cosx=.

≤cosx<1,0<x≤.   

+.∵

∴sin<sin(+)≤1. +<sin(+)+≤1+,

f(x)的值域为(2,1+).     

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