做匀加速直线运动的物体,依次通过A、B、C三点,位移sAB=sBC,已知

做匀加速直线运动的物体,依次通过A、B、C三点,位移sAB=sBC,已知物体在AB段的平均速度为3 m/s,在BC段的平均速度为6 m/s,则物体在B点的瞬时速度为(  )

A.4 m/s                 B.4.5 m/s

C.5 m/s                 D.5.5 m/s

答案

C

解析:物体运动示意图如图所示,设物体在A、B、C三点的瞬时速度分别为vA、vB、vC,则:

                             ①

=6                              ②

                           ③

联立①②③解得vB=5 m/s.

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