在一真空密闭容器中,通入一定量气体A在一定条件下,发生如下反

在一真空密闭容器中,通入一定量气体A在一定条件下,发生如下反应:

2A(g)  B(g) + xC(g),反应达平衡时,测得容器内压强增大为P%,若此时A的转化率为a%,下列关系正确的是(   )

A.若x=1,则P=a              B.若x=2,则P=a

C.若x=3,则P=a               D.若x=4,则P=a

 

答案

C

解析:                       2A(g)  B(g) + xC(g)

起始量(mol)                1          0      0

转化量(mol)                a%       0.5a%  0.5ax%

平衡量(mol)               1-a%      0.5a%  0.5ax%

由题意知0.5a%+0.5ax%+1-a%-1=p%

解得ax-a=2p

所以选项C 正确。

 

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