如图(a)所示,两个平行金属板P、Q竖直放置,两板间加上如图(b

如图(a)所示,两个平行金属板PQ竖直放置,两板间加上如图(b)所示的电压.t=0时,Q板比P板电势高5V,此时在两板的正中央M点有一个电子,速度为零,电子在电场力作用下运动,使得电子的位置和速度随时间变化.假设电子始终未与两板相碰.在0t8×10-10s的时间内,这个电子处于M点的右侧,速度方向向左且大小逐渐减小的时间是

A0t2×10-10s                 B2×10-10st4×10-10s

C4×10-10st6×10-10s           D6×10-10st8×10-10s

答案

D

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