证明:(1)如图(一),连接

,

∵

为⊙

的直径 ∴

∴

为⊙

的直径 ∴

在

上
又

,

为

的中点
∴△

是以

为底边的等腰三角形
∴

····················································································· (3分)
(2)如图(二),连接

,并延长

交⊙

与点

,连

∵四边形

内接于⊙

∴

又∵

∴

∴

又

为⊙

的直径 ∴

∴

···················································································· (3分)
(3)如图(三),连接

,并延长

交⊙

与点

,连

∵

又

∴
∴

又

∴

···················································································· (3分)解析:
略