如图2-10所示,站在汽车上的人用手推车的力为F,脚对车向后的静摩

如图2-10所示,站在汽车上的人用手推车的力为F,脚对车向后的静摩擦力为F′,下列说法正确的是(    )

图2-10

A.当车匀速运动时,F和F′所做的总功为零

B.当车加速运动时,F和F′的总功为负功

C.当车加速运动时,F和F′的总功为正功

D.不管车做何种运动,F和F′的总功都为零

答案

解析:当车匀速运动时,总动能不变,故F和F′所做的总功为零;当车加速运动时,对人总动能增加,合外力对人做正功,故F和F′的总功为负功.

答案:AB

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