若函数f(x)=kx2+(k-1)x+2是偶函数,则f(x)的递减区间是________.

若函数f(x)kx2(k1)x2是偶函数,则f(x)的递减区间是________

答案

解析:f(x)是偶函数,

f(x)kx2(k1)x2kx2(k1)x2f(x)

k1.

f(x)x22,其递减区间为(0]

答案:(0]

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