如图,△ABC是⊙O的内接三角形,AB为⊙O的直径,点D为⊙O上一点,若∠CAB=55°,则∠ADC的大小为________(度).
35 解析:∵AB为⊙O的直径,∴∠ACB=90°,又∵∠CAB=55°,∴∠ABC=35°,∴∠ADC=∠ABC=35°.