A.x1+x2<0 B.x12>x22 C.x1<x2 D.x12<x22
解析:据题意可知函数f(x)=cosx在[0,1]上是减函数,且为偶函数,故f(x1)>f(x2)f(|x1|)>f(|x2|)|x1|<|x2|即x12<x22.