不等式≥2的解集为 A.[-1,0)                          

不等式≥2的解集为

A.[-1,0)                                                      B.[-1,+∞)

C.(-∞,-1]                                                 D.(-∞,-1]∪(0,+∞)

答案

A


解析:

本题考查分式不等式的解法.

原不等式可化为-2≥0,

≥0.

整理得≥0,即≤0.

利用“穿线法”解此分式不等式,如上图所示.

所以不等式的解集为{x|-1≤x<0}.

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