已知:TiO2(s)+2Cl2(g)===TiCl4(l)+O2(g) ΔH=+140 kJ·mol-1 2C(s)+O2(g)===2

 已知:TiO2(s)2Cl2(g)===TiCl4(l)O2(g) ΔH=+140 kJ·mol1

2C(s)O2(g)===2CO(g) ΔH=-221 kJ·mol1

则反应TiO2(s)2Cl2(g)2C(s)TiCl4(l)2CO(g) ΔH

A—162 kJ·mol1       B.+81 kJ·mol1    

C.+162 kJ·mol1       D.-81 kJ·mol1

答案

D

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