已知:TiO2(s)+2Cl2(g)===TiCl4(l)+O2(g) ΔH=+140 kJ·mol-1
2C(s)+O2(g)===2CO(g) ΔH=-221 kJ·mol-1
则反应TiO2(s)+2Cl2(g)+2C(s)=TiCl4(l)+2CO(g) ΔH为
A.—162 kJ·mol-1 B.+81 kJ·mol-1
C.+162 kJ·mol-1 D.-81 kJ·mol-1
已知:TiO2(s)+2Cl2(g)===TiCl4(l)+O2(g) ΔH=+140 kJ·mol-1
2C(s)+O2(g)===2CO(g) ΔH=-221 kJ·mol-1
则反应TiO2(s)+2Cl2(g)+2C(s)=TiCl4(l)+2CO(g) ΔH为
A.—162 kJ·mol-1 B.+81 kJ·mol-1
C.+162 kJ·mol-1 D.-81 kJ·mol-1
D