已知直线Ax+By+C=0的斜率小于0,若A、B、C从-5,-3,-1,0,2,4,7,9这

已知直线Ax+By+C=0的斜率小于0,若A、B、C从-5,-3,-1,0,2,4,7,9这8个数中选取3个不同的数,则能确定不同的直线条数是(    )

A.72                    B.108                   C.126                  D.252

答案

B

解析:由已知得A,B同号,故·+·=108条直线满足.

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