(山东省临沂市):如图5-3所示,我国自主制造的“蛟龙号”载人

(山东省临沂市):如图53所示,我国自主制造的“蛟龙号”载人潜水器,某次试潜顺利完成下潜5000m深度,此次下潜全过程的平均速度约为0.6m/s,潜到最深处时海水对“蛟龙号”外壳的压强达5×107pa

 1)求“蛟龙号”本次下潜过程所用的时间约为多少?

  2)如果“蛟龙号”潜水器一个观测窗的面积约为0.03m2,则潜到最深处时海水对该观测窗的压力约为多大?

 

答案

1)下潜过程所用的时间:t8333s

 2)海水对该观测窗的压力:F=PS=5×107pa×0.03m2=1.5×106N

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