已知常温下在溶液中可发生如下两个离子反应: Ge4++Fe2+===Fe3+

已知常温下在溶液中可发生如下两个离子反应:

Ge4Fe2===Fe3Ge3      Sn22Fe3===2Fe2Sn4 

由此可以确定Fe2Ge3Sn2三种离子的还原性由强到弱的顺序是

        ASn2Fe2Ge3                       BSn2Ge3Fe2

        CGe3Fe2Sn2                        DFe2Sn2Ge3

 

答案

A

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