已知绵羊角的表现型与基因型的关系如下,正确的判断是( ) 基因

已知绵羊角的表现型与基因型的关系如下,正确的判断是(  )

基因型

HH

Hh

hh

公羊的表现型

有角

有角

无角

母羊的表现型

有角

无角

无角

A.若双亲无角,则子代全部无角

B.若双亲有角,则子代全部有角

C.若双亲基因型为Hh,则子代有角与无角的数量比为11

D.绵羊角的性状遗传不遵循基因的分离定律

答案

解:A、双亲无角,如果母本是Hh,则子代雄性个体中会出现有角,故A不正确;

B、双亲有角,如果父本是Hh,母本是HH,则子代中雌性个体Hh会出现无角,故B不正确;

C、双亲基因型为Hh,则子代雄性个体中有角与无角的数量比为31,雌性个体中有角与无角的数量比为13,所以子代有角与无角的数量比为11,故C正确;

D、绵羊角的性状遗传符合孟德尔的基因分离定律,在减数分裂过程,等位基因Hh发生分离,故D不正确.

故选:C

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