从方框中选择恰当的句子补全对话,其中有两项多余。         

从方框中选择恰当的句子补全对话,其中有两项多余。                 

A: Good morning, Xincheng Hotel. Can I help you?

B: Good morning,     71   

A: OK. We have rooms with a bathroom, TV, refrigerator and air conditioning.     72   

Also, from the windows you can see a beautiful park near our hotel.

B:     73   

A: A standard room with two single beds costs 150 and a room with one single bed costs

120.     74   

B: OK. I want to book two standard rooms with two single beds and one room with one single bed.

A: How long will you stay?

B: About two days.

A: All right. Two standard rooms with two single beds and one room with one single bed.

Please pay for the rooms before 17:30.    75   

B: I’m Li Zhi and my telephone number is 8267-6936. Thank you.

A: You’re welcome.

A. They are very comfortable.

B. How many standard rooms do you want?

C. I want to make a room reservation.

D. Have a good time!

E. Your name and telephone number, please.

F. What about the price?

G. Sounds exciting!

  

71. __________ 72. __________ 73. __________ 74. __________ 75. __________

 

答案

C A F B E 

相关题目

下列操作中,不正确的是A.用胶头滴管向试管中滴加液体时,
下列操作中,不正确的是A.用胶头滴管向试管中滴加液体时,把滴管伸入试管内B.把氢氧化钠固体放在天平左盘的玻璃器皿中称量C.在实验室里制取CO2气
在秦朝,被称为“百官之首”的是 A.三公          B.
在秦朝,被称为“百官之首”的是 A.三公          B.丞相            C.太尉               D.御史大夫
在浓盐酸中H3AsO3与SnCl2反应的离子方程3SnCl2+12Cl-+2H3AsO3+6
在浓盐酸中H3AsO3与SnCl2反应的离子方程3SnCl2+12Cl-+2H3AsO3+6H+=2As+3SnCl62++6M。关于该反应的说法中正确的组合是:①氧化剂是H3AsO3;②还原性:Cl-
(1)△ABC和△CDE是两个等腰直角三角形,如图1,其中∠ACB=
(1)△ABC和△CDE是两个等腰直角三角形,如图1,其中∠ACB=∠DCE=90°,连结AD、BE,求证:△ACD≌△BCE. (2)△ABC和△CDE是两个含30°的直角三角形,
(本题满分10分)如图,是直角三角形,,以AB为直径的⊙O交于
(本题满分10分)如图,是直角三角形,,以AB为直径的⊙O交于点E,点D是BC边的中点,连结.(1)试判断直线DE与⊙O的位置关系?并说明理由;(2)若⊙O
(6分)使用价电子对互斥理论,推测下列分子构型,并画出
(6分)使用价电子对互斥理论,推测下列分子构型,并画出示意图。ICl2-      ICl4-      IF3      IF5
如图所示,小物体位于半径为R的半球顶端,若给小物体以水
如图所示,小物体位于半径为R的半球顶端,若给小物体以水平初速度时,小物体对球顶恰无压力,则: A、物体恰好沿球面做圆周运动      B、物体
    you        the radio in English?A.How about; listening toB.W
    you        the radio in English?A.How about; listening toB.Why not; listenC.Will; listenD.Why don’t; listen to

最新题目