A.f(k+1)=f(k)+k-1 B.f(k+1)=f(k)+k+1
C.f(k+1)=f(k)+k D.f(k+1)=f(k)+k+2
解析:在k条直线的基础上增加一条即第k+1条直线,该直线与前k条直线每条有1个交点,共增加k个交点,故f(k+1)=f(k)+k.
答案:C