标有“6V 1.5W”的小灯泡,通过它的电流随两端电压变化的关系如图

标有“6V 1.5W”的小灯泡,通过它的电流随两端电压变化的关系如图所示,若把这样的三只灯泡串联起来,接在12V的电源两端,灯泡的电阻及实际功率约为:

A.24Ω  0.67W   B.20Ω  0.8W    C.24Ω  0.96W     D.20Ω  0.67W

 

答案

B

解析:若把这样的三只灯泡串联起来,接在12V的电源两端,每一个灯泡的实际电压是4V,由图像可知,电路中的电流是0.2A。灯泡的电阻是4V/0.2A=20欧,实际功率约为P=UI=0.8W.

 

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