在反应X+2Y====R+2M中,已知R和M的摩尔质量之比为22∶9,当1.6 g X与Y完

在反应X+2Y====R+2M中,已知R和M的摩尔质量之比为22∶9,当1.6 g X与Y完全反应后,生成4.4 g R。则在此反应中Y和M的质量之比为(    )

A.16∶9            B.23∶9                C.32∶9          D.46∶9

答案

A


解析:

假设R与M的摩尔质量分别为r g·mol-1和m g·mol-1,有r/m=22/9。又假设参加反应的Y为ag,生成的M为b g。根据质量守恒定律可列出关系式:1.6+a=4.4+b,化简得a=b+2.8。

    再据方程式的比例式可得:8.8m=rb,b=3.6,

    所以a/b=(b+2.8)/b=(3.6+2.8)/3.6=16/9。

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