(A)1 (B)2 (C)3 (D)4
B∵M∩{a1,a2,a3}={a1,a2},
∴a1∈M,a2∈M,a3M.
又∵M{a1,a2,a3,a4},∴M为{a1,a2}或{a1,a2,a4},故选B.