如图所示,R1=10 ,R2=15 ,电流表示数是1A,求:
(1)R1中电流I1和R2中I2各是多大?
(2)电压表的示数是多大?
解: R总=R1R2/(R1+R2)=6Ώ
U=IR=1A×6Ώ=6V
I1=U/R1=6V/10Ώ=0.6A
I2=U/R2=6V/15Ώ=0.4A