有一电阻为30Ω的电灯,在正常工作时它两端的电压为12V。要把电灯

有一电阻为30Ω的电灯,在正常工作时它两端的电压为12V。要把电灯接在36V的电路上,需要给它________联一个_______Ω的电阻。

答案

串  60 


解析:

电源电压比用电器两端的电压要高,所以要利用串联来分电压(如图所示)。串联电阻大小为

 方法一: UL=12V,U=36V ,U0=U-UL=24V

          IL=I0=0.4A  。R0=60Ω

 方法二:IL=I0=0.4A  R=90Ω

R0=R-RL=60Ω

  【命题立意】本题考查了利用串联电阻可以分电压的方法使灯泡能正常工作的

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