某小组测酱油的密度,在烧杯中倒入适量的酱油,测出烧杯和酱油的

某小组测酱油的密度,在烧杯中倒入适量的酱油,测出烧杯和酱油的总质量是82.4g,将烧杯中一部分酱油倒入量筒中,如甲图所示,测量烧杯和剩余酱油的质量时,所加砝码和游码位置如乙图所示,那么量筒中酱油的质量为  g,由此可计算出酱油的密度为  kg/m3

答案

            解:

烧杯和剩余酱油的质量:m'=50g+10g+1.4g=61.4g

量筒中酱油的质量为:m=m0m'=82.4g61.4g=21g

量筒中酱油的体积:V=20ml=20cm3

酱油的密度是:ρ===1.05g/cm3=1.05×103kg/m3

故答案为:211.05×103

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