已知实数x、y满足|tanx|+|tany|>|tanx+ tany|,且y∈(π,π),则|tan x -tan y|

已知实数x、y满足|tanx|+|tany|>|tanx+ tany|,且y∈(π,π),则|tan x -tan y|等于(  )

A.tanx-tanyB.tany-tanxC.tanx+tanyD.|tany|-|tanx|



答案

答案:B

解析:由题意可知tanx与tany异号,又tany>0,故tanx<0,∴tanx-tany<0.∴|tanx-tany|=-(tanx-tany)=tany-tanx.

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