若x,y是正数,则(x+)2+(y+)2的最小值是(    )A.3             B.

若x,y是正数,则(x+2+(y+)2的最小值是(    )

A.3             B.             C.4             D.

答案

解析

:(x+2+(y+)2=(x2+)+(y2+)+(+)≥2+2+2=4,

当且仅当即x=y=取等号.

答案

:C

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