设{an}是等差数列,a3+a4+a5=9,a10=9,则这个数列的前10项和为(    )A

设{an}是等差数列,a3+a4+a5=9,a10=9,则这个数列的前10项和为(    )

A.35             B.40           C.45            D.50

答案

答案:

C  【解析】本题考查等差数列的性质、通项公式及等差数列的前n项和公式等知识.在等差数列中,由a3+a4+a5=3a4=9,∴a4=3,∵a10=a4+6d=9,∴d=1,可得a1=0,所以S10==45.

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