如图,已知⊙O的弦CD垂直于直径AB,点E在CD上,且EC = EB .
(1)求证:△CEB∽△CBD ;
(2)若CE = 3,CB=5 ,求DE的长.
如图,已知⊙O的弦CD垂直于直径AB,点E在CD上,且EC = EB .
(1)求证:△CEB∽△CBD ;
(2)若CE = 3,CB=5 ,求DE的长.
(1)证明:∵弦CD垂直于直径AB ∴BC=BD ∴∠C =∠D 又∵EC = EB
∴∠C =∠CBE ∴∠D =∠CBE 又∵∠C =∠C ∴△CEB∽△CBD
(2)解:∵△CEB ∽△CBD ∴ ∴CD=
∴DE = CD-CE =
-3 =
解析:略