室温时,两个容积相同的烧瓶中分别盛有M和N两种气体(同温同压),取下

室温时,两个容积相同的烧瓶中分别盛有M和N两种气体(同温同压),取下弹簧夹A,使两烧瓶内的气体接触(如图),容器内的压强由大到小的顺序是

A.①②③④           B.②④①③

C. ④①②③            D.①④③②

【解析】若设气体的物质的量均是1mol,则①中反应为2H2S+SO2=3S+2H2O,剩余气体是0.5mol。②中不反应,气体的物质的量是2mol,③中反应是NH3+HCl=NH4Cl,没有气体剩余。④中反应为2NO+O2=2NO2,剩余气体是1.5mol。所以答案选B。

 

答案

B

 

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