(A)af(a) ≤f(b) (B)bf(b) ≤f(a) (C)af(b) ≤bf(a) (D )bf(a)≤af(b)
答案:C
解析:∵xf′(x)+f(x)≤0,
∴f′(x)≤-≤0.
∴f(x)单调递减.
∴≤,
即af(b)≤bf(a).