若实数x,y满足xy>0,且x2y=2,则xy+x2的最小值是(    )A.1        

若实数x,y满足xy>0,且x2y=2,则xy+x2的最小值是(    )

A.1          B.2           C.3          D.4

答案

思路解析:

xy+x2=2xy+xy+x2=1.

答案:

A

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